Deployment System for bughouse Tournament of Individuals with changing partners
(Tournament with changing partners in bughouse double board chess team game)

1-2
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3-4 Z system (v.0.20)

Initial assumptions
 The number of players N is equal to 4K, where k> 1. (i.e. 8, 12, 16 etc.)

The player's start number is determined by his playing power (BELO), descending, ie the lowest number has the strongest player.

Rounds mounting:
1. round
  The players are divided into pairs according to the number: 1 + 2,3 + 4, .., (N-1) + N
  1 s 2 against N-1 with N, 3 s 4 against N-3 with N-2, ..., N / 2-1 with N / 2 against N / 2 + 1 with N / 2 + 2
  Note abbreviations can be used for writing: '+' corresponds to 'with', 'x' corresponds to 'against'
  E.g. for 8 players: 1 + 2 x 7 + 8, 3 + 4 x 5 + 6, for 12 players: 1 + 2 x 11 + 12, 3 + 4 x 9 + 10, 5 + 6 x 7 + 8, etc. for more.

2nd and next rounds
 (1) Determined player order
   Determine the order of the Players after the previous round according to the following criteria:
   1.Points, 2.Progress (Sum of points achieved after rounds), 3.Start number
   players will be ordered in descending order, everyone receives a number, ie a player with most points and the best progress ... is number 1
 (2) Determining of squares (square = 4 players on two chessboards who will play bughouse game)
   The players are divided from the top (number 1) into squares:
   1. square players with number 1,2,3,4; 2nd square 5,6,7,8 etc. last square N-3, N-2, N-1, N
 (3) Deployment of pairs within a square
   The player gains a number within the square according to the number in the sequence: simply the lowest is 1, the second lowest 2, etc.
     e.g., 5,6,7,8 -> 1,2,3,4
   Now (A1) if the same players did not play 1 + 3 x 2 + 4 in the last round, then I play.
     thus, for example, 5 + 7 x 6 + 8; the exception is the first square, in which 1 + 4 x 2 + 3 is played
   Or (A2) if the same players 1 + 3 x 2 + 4 have already played in the last round, there is a rotation and I play 1 + 4 x 2 + 3
     thus, for example, 5 + 8 x 6 + 7; in the case of the first square 1 + 3 x 2 + 4
   The important exception is the first square, in the first square I always play 1 + 4 x 2 + 3
   and if they played together in the last round there is a rotation to 1 + 3 x 2 + 4.

Number of games in one round
  In one round I will play pairs of 2 games against each other,
    two-part rounds are probably the most suitable in terms of time / player rotation ratio
 Note The players choose the colors themselves, in case they can't decide,
   because someone wants to play against a specific one of two opponents,
   the pair will determine by lot who is sitting first. You can also use the system that first sits the lowest number.
 Note In the pair that loses in the first game, the players have to change colors, the winners can.

Number of rounds in the tournament
  at least 20 is suitable.

Other number of players than 4K
 If the number of players is 4K + 2 (ie 10, 14, etc.)
   will play the middle (for example if 18 players number 9 and number 10) pair against each other (simultaneously on two boards).
 If the number of players is 4K + 1 (ie 9, 13, etc.)
   the last one gains default points.
 If the number of players is 4K + 3 (ie 11, 15, etc.)
   the middle pair plays against each other and the last player gains default points.